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Move getTldFromDomainName into DomainNameUtils
------------- Created by MOE: https://github.com/google/moe MOE_MIGRATED_REVID=118475557
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@@ -14,7 +14,10 @@
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package com.google.domain.registry.util;
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import static com.google.common.base.Preconditions.checkArgument;
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import com.google.common.base.Ascii;
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import com.google.common.base.Strings;
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import com.google.common.net.InternetDomainName;
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/** Utility methods related to domain names. */
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@@ -38,5 +41,27 @@ public final class DomainNameUtils {
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return Idn.toASCII(Ascii.toLowerCase(label));
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}
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/**
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* Returns the canonicalized TLD part of a valid domain name (just an SLD, no subdomains) by
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* stripping off the leftmost part.
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*
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* <p>This function is compatible with multi-part tlds, e.g. {@code co.uk}. This function will
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* also work on domains for which the registry is not authoritative. If you are certain that the
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* input will be under a TLD this registry controls, then it is preferable to use
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* {@link com.google.domain.registry.model.registry.Registries#findTldForName(InternetDomainName)
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* Registries#findTldForName}, which will work on hostnames in addition to domains.
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*
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* @param fullyQualifiedDomainName must be a punycode SLD (not a host or unicode)
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* @throws IllegalArgumentException if there is no TLD
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*/
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public static String getTldFromDomainName(String fullyQualifiedDomainName) {
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checkArgument(
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!Strings.isNullOrEmpty(fullyQualifiedDomainName),
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"fullyQualifiedDomainName cannot be null or empty");
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InternetDomainName domainName = InternetDomainName.from(fullyQualifiedDomainName);
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checkArgument(domainName.hasParent(), "fullyQualifiedDomainName does not have a TLD");
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return domainName.parent().toString();
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}
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private DomainNameUtils() {}
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}
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