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test: cqlpy: add test for create keyspace with no options specified

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This patch introduces one new test case. It tests that a keyspace
can be created without specifying replication options. Since other
options already had defaults, this test assures a keyspace can
be created with no options specified at all, with the following query:
`CREATE KEYSPACE ks;`

Refs #25145
This commit is contained in:
Dario Mirovic
2025-09-08 10:08:23 +02:00
parent 20c173e958
commit d92ceed19a
1 changed files with 7 additions and 6 deletions
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13
test/cqlpy/test_keyspace.py
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@@ -47,6 +47,13 @@ def test_create_and_drop_keyspace_with_default_replication_options(cql, this_dc)
with new_test_keyspace(cql, "WITH REPLICATION = {}") as keyspace:
assert_keyspace(cql, keyspace, "org.apache.cassandra.locator.NetworkTopologyStrategy", this_dc)
# The "WITH REPLICATION" part of CREATE KEYSPACE may be omitted.
# Trying to create a keyspace with no replication options at all
# should result in NetworkTopologyStrategy and replication factor of 1 being set by default.
def test_create_and_drop_keyspace_with_no_replication_options(cql, this_dc):
with new_test_keyspace(cql, "") as keyspace:
assert_keyspace(cql, keyspace, "org.apache.cassandra.locator.NetworkTopologyStrategy", this_dc)
# Trying to create the same keyspace - even if with identical parameters -
# should result in an AlreadyExists error.
def test_create_keyspace_twice(cql, this_dc):
@@ -65,12 +72,6 @@ def test_create_keyspace_if_not_exists(cql, this_dc):
cql.execute("CREATE KEYSPACE IF NOT EXISTS test_create_keyspace_if_not_exists WITH REPLICATION = { 'class' : 'SimpleStrategy', 'replication_factor' : 2 }")
cql.execute("DROP KEYSPACE test_create_keyspace_if_not_exists")
# The "WITH REPLICATION" part of CREATE KEYSPACE may not be omitted - trying
# to do so should result in a syntax error:
def test_create_keyspace_missing_with(cql):
with pytest.raises(SyntaxException):
cql.execute("CREATE KEYSPACE test_create_and_drop_keyspace")
# The documentation states that "Keyspace names can have alpha-
# numeric characters and contain underscores; only letters and numbers are
# supported as the first character.". This is not accurate. Test what is actually