f3eade2f62
Drop the AGPL license in favor of a source-available license. See the blog post [1] for details. [1] https://www.scylladb.com/2024/12/18/why-were-moving-to-a-source-available-license/
98 lines
5.3 KiB
Python
98 lines
5.3 KiB
Python
# Copyright 2022-present ScyllaDB
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#
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# SPDX-License-Identifier: LicenseRef-ScyllaDB-Source-Available-1.0
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#############################################################################
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# Various tests for static-column support in Scylla.
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# Note that we have many more tests for static columns in other test
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# frameworks (C++, cql, dtest) but the benefit of these tests is that they
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# allow running tests with debatable behavior on Cassandra as well.
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#############################################################################
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import pytest
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from .util import new_test_table, unique_key_int
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@pytest.fixture(scope="module")
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def table1(cql, test_keyspace):
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schema='p int, c int, r int, s int static, PRIMARY KEY(p, c)'
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with new_test_table(cql, test_keyspace, schema) as table:
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yield table
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# Test what happens when we SELECT a partition which has a static column
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# set but no clustering row, but the static column is *not* selected.
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# Reproduces issue #10091.
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#
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# Marking this issue "xfail" because Scylla and Cassandra differ in behavior
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# and we have no good explanation why Scylla's behavior is more correct than
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# Cassandra. If we later decide that we consider *both* behaviors equally
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# correct, we can change the test to accept both and make it pass.
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@pytest.mark.xfail(reason="issue #10091")
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def test_static_not_selected(cql, table1):
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p = unique_key_int()
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# The partition p doesn't exist, so the following select yields nothing:
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assert list(cql.execute(f'SELECT * FROM {table1} WHERE p={p}')) == []
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# Insert just the static column, and no clustering row:
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cql.execute(f'INSERT INTO {table1} (p, s) values ({p}, 1)')
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# If we select all the columns, including the static column s, SELECTing
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# the partition gives us one "row" with the static column set and all
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# other columns set to null - otherwise the static column cannot be
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# returned.
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assert list(cql.execute(f'SELECT * FROM {table1} WHERE p={p}')) == [(p,None,1,None)]
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# But what happens if we SELECT just regular (non-static) columns?
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# Should the SELECT return nothing (since there is no clustering row),
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# or return one "row" with null columns (basically just like in the
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# previous SELECT, just intersected with the desired column)?
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# Currently, Cassandra does the former, Scylla does the latter,
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# so the following assert fails on Scylla:
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assert list(cql.execute(f'SELECT r FROM {table1} WHERE p={p}')) == []
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# Verify that if a partition has a static column set, reading an *existing*
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# clustering row will return it, but reading a *non-existing* row will not
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# return anything - not even the static column.
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#
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# Contrast this with issue #10081 (test_lwt.py::test_lwt_missing_row_with_static)
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# where we suggested that in an UPDATE with IF condition (LWT), the static
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# columns should be readable in the condition expression, whether or not the
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# given row exists.
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def test_missing_row_with_static(cql, table1):
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p = unique_key_int()
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# Insert into partition p just static column and once clustering row c=2
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cql.execute(f'INSERT INTO {table1}(p, s, c, r) values ({p}, 1, 2, 3)')
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# If we SELECT row c=2, we get it and the static column:
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assert list(cql.execute(f'SELECT p, s, c, r FROM {table1} WHERE p={p} AND c=2')) == [(p, 1, 2, 3)]
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# If we SELECT row c=1 (which doesn't exist), we get nothing - not even
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# the static column
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assert list(cql.execute(f'SELECT p, s, c, r FROM {table1} WHERE p={p} AND c=1')) == []
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# Verify that if a partition has a static column set, filtering it (with
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# ALLOW FILTERING) based on regular columns will need to find clustering
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# rows which actually match this filter - and can't return only a static
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# row (which doesn't match the filter). This is similar to the previous test
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# (test_missing_row_with_static) except that the filter here is on a regular
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# column, not a clustering column.
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def test_filter_with_static(cql, table1):
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p = unique_key_int()
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# Insert into partition p just static column and one clustering row
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# with its regular column r set to 3:
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cql.execute(f'INSERT INTO {table1}(p, s, c, r) values ({p}, 1, 2, 3)')
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# If we filter for r=3, we expect to get the clustering row and the
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# static column:
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assert list(cql.execute(f'SELECT p, s, c, r FROM {table1} WHERE p={p} AND r=3 ALLOW FILTERING')) == [(p, 1, 2, 3)]
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# If we filter for r=4, we expect to get nothing - not even the static
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# column. Getting back just the static row, with r=null, would be wrong
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# because it does *not* match the filter r=4.
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assert list(cql.execute(f'SELECT p, s, c, r FROM {table1} WHERE p={p} AND r=4 ALLOW FILTERING')) == []
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# Reproduce issue #10357. The query is identical to the one in the above
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# test (test_filter_with_static), but here the partition has only a static
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# column value, and no clustering row at all. We expect to get back nothing
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# when using a filtering on a regular column.
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def test_filter_with_only_static(cql, table1):
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p = unique_key_int()
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cql.execute(f'INSERT INTO {table1}(p, s) values ({p}, 1)')
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# There are no clustering rows or r column set for anything, so filtering
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# for r=4 should return nothing. But issue #10357 caused Scylla to wrongly
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# return a row with only the static value - which doesn't match the filter.
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assert list(cql.execute(f'SELECT p, s, c, r FROM {table1} WHERE p={p} AND r=4 ALLOW FILTERING')) == []
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