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28b972a588
The function currently assumes that shard assignment for subsequent tokens is round robin, which will not be the case for tablets. This can lead to incorrect split calculation or infinite loop. Another assumption was that subsequent splits returned by the sharder have distinct shards. This also doesn't hold for tablets, which may return the same shard for subsequent tokens. This assumption was embedded in the following line: start_token = sharder.token_for_next_shard(end_token, shard); If the range which starts with end_token is also owned by "shard", token_for_next_shard() would skip over it.