A type trait (is_variant_element) and a concept (VariantElement) that tell if a type T is a member of a variant or not. It can be used even if the variant's elements are not yet defined (just forward-declared).
50 lines
1.5 KiB
C++
50 lines
1.5 KiB
C++
/*
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* Copyright (C) 2021-present ScyllaDB
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*/
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/*
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* This file is part of Scylla.
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*
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* Scylla is free software: you can redistribute it and/or modify
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* it under the terms of the GNU Affero General Public License as published by
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* the Free Software Foundation, either version 3 of the License, or
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* (at your option) any later version.
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*
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* Scylla is distributed in the hope that it will be useful,
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* but WITHOUT ANY WARRANTY; without even the implied warranty of
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* MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
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* GNU General Public License for more details.
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*
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* You should have received a copy of the GNU General Public License
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* along with Scylla. If not, see <http://www.gnu.org/licenses/>.
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*/
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#pragma once
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#include <variant>
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#include <type_traits>
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namespace utils {
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// Given type T and an std::variant Variant, return std::true_type if T is a variant element
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// This is also the recursion base case (empty variant), so return false.
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template <typename T, typename Variant>
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struct is_variant_element : std::false_type {
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};
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// Match - return true
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template <typename T, typename... Elements>
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struct is_variant_element<T, std::variant<T, Elements...>> : std::true_type {
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};
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// No match - recurse
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template <typename T, typename U, typename... Elements>
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struct is_variant_element<T, std::variant<U, Elements...>> : is_variant_element<T, std::variant<Elements...>> {
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};
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// Givent type T and std::variant, true if T is one of the variant elements.
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template <typename T, typename Variant>
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concept VariantElement = is_variant_element<T, Variant>::value;
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}
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