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Align first free ino to lock group

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Currently the first inode number that can be allocated directly follows
the root inode.  This means the first batch of allocated inodes are in
the same lock group as the root inode.

The root inode is a bit special.  It is always hot as absolute path
lookups and inode-to-path resolution always read directory entries from
the root.

Let's try aligning the first free inode number to the next inode lock
group boundary.  This will stop work in those inodes from necessarily
conflicting with work in the root inode.

Signed-off-by: Zach Brown <zab@versity.com>
This commit is contained in:
Zach Brown
2021-05-24 13:23:46 -07:00
parent e6889b1882
commit f2c9f66385
1 changed files with 1 additions and 1 deletions
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utils/src/mkfs.c
+1 -1
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@@ -197,7 +197,7 @@ static int do_mkfs(struct mkfs_args *args)
memset(super, 0, SCOUTFS_BLOCK_SM_SIZE);
super->version = cpu_to_le64(SCOUTFS_INTEROP_VERSION);
uuid_generate(super->uuid);
super->next_ino = cpu_to_le64(SCOUTFS_ROOT_INO + 1);
super->next_ino = cpu_to_le64(round_up(SCOUTFS_ROOT_INO + 1, SCOUTFS_LOCK_INODE_GROUP_NR));
super->next_trans_seq = cpu_to_le64(1);
super->total_meta_blocks = cpu_to_le64(last_meta + 1);
super->first_meta_blkno = cpu_to_le64(next_meta);